msa測量系統分析(ppt136頁)-資料下載頁

　　

【正文】 GRR 報告 SPB 001 T est Name: BST70297 B I A S L I N E A R I T Y Machi ne : DAGEDate : May. 739。98 1. Bi as (Indep ende nt Samp le Metho d)5 0 . 1 0 5 1 . 9 05 2 . 6 0 5 1 . 2 0 B i a s = Obse r ved Aver age Master Measur emen t5 2 . 2 0 5 3 . 0 0 = 3. 094 9 . 8 0 4 9 . 7 05 3 . 4 0 5 3 . 2 0 P r o c e s s V a r ia t io n ( 6 s ig m a r a n g e ) = 42. 50 % B i a s = 100 [ Bi as / Pr o cess Var iatio n]51. 71 54. 80=7. 27% 2. Li near ity ==Par ts 1 2 3 4 = 0. 1422Master value 55. 79 54. 70 54. 50 54. 801 5 8 . 2 0 5 9 . 9 0 4 8 . 7 0 4 6 . 8 02 5 9 . 6 0 6 0 . 2 0 4 9 . 8 0 4 7 . 5 0 = = 4. 414T 3 5 8 . 4 0 5 9 . 1 0 4 8 . 6 0 4 8 . 9 0R 4 5 5 . 0 0 5 4 . 1 0 5 0 . 8 0 5 0 . 0 0I 5 4 8 . 2 0 4 3 . 8 0 4 9 . 6 0 4 9 . 5 0A 6 4 8 . 0 0 4 6 . 3 0 4 8 . 6 0 4 6 . 7 0 = = 0. 21L 7 4 8 . 9 0 4 8 . 2 0 4 8 . 7 0 4 9 . 2 0S 8 4 7 . 7 0 4 5 . 6 0 4 9 . 2 0 5 0 . 1 09 4 7 . 6 0 4 5 . 6 0 6 9 . 5 0 6 8 . 7 010 5 2 . 0 0 5 3 . 4 0 5 0 . 1 0 5 1 . 2 0 L i n e r a r i t y = S l o p e x Pr o cess Var iatio n Par t Avg. 52. 360 51. 620 51. 360 50. 860 = 6. 0414Bi as 3. 430 3. 080 3. 140 3. 940 % L i n e a r i t y= 100 [ Li near ity / Pr o cess Var iatio n ]= 14. 22% Go o dnes s o f F it ( ) = 0. 21?1?2?3?4?6?7?8?9?10?m a s?obsaxyx y???? (n)by a x?R2[ ]yyn22???[ ]xxn22???a b? ??5R2y[ ]xyx yn????2xxn22??? ( )第九版： 1999年 2月 131 MSA BST 偏倚 線性 S P B 0 0 1 N B R : A P 0 0 37 0 2 9 7 D a t e : M a y 0 7 . 39。 9 8P a c k a g e : S O 2 0 L D M a c h i n e : D A G ET e s t n a m e : B PT ( G / W : 1 . 0 M I L )R E P E A T A B I L I T Y A N D R E P R O D U C I B I L I T Y D A T A S H E E T1 2 3 4 5 6 7 8 9 10 11 12 XO P E R A T O R K 1 3 1 2 5 K 1 6 2 9 3 K 1 6 5 3 8S A M P L E 1 S T T RIA L 2 N D T RIA L 3 RD T RIA L RA N G E 1 S T T RIA L 2 N D T RIA L 3 RD T RIA L RA N G E 1 S T T RIA L 2 N D T RIA L 3 RD T RIA L RA N G E1 1 0 . 0 0 1 0 . 1 0 9 . 9 0 0 . 2 0 9 . 4 5 9 . 5 0 9 . 4 0 0 . 1 0 9 . 7 0 9 . 5 0 9 . 9 0 0 . 4 0 9 . 7 22 1 2 . 4 0 1 2 . 1 2 1 2 . 3 6 0 . 2 8 1 2 . 6 2 1 2 . 3 5 1 2 . 5 7 0 . 2 7 1 2 . 4 9 1 2 . 5 2 1 2 . 5 5 0 . 0 6 1 2 . 4 43 1 2 . 2 3 1 2 . 1 1 1 2 . 4 5 0 . 3 4 1 2 . 5 6 1 2 . 2 7 1 2 . 2 3 0 . 3 3 1 2 . 4 1 1 2 . 6 3 1 2 . 4 1 0 . 2 2 1 2 . 3 74 1 2 . 4 5 1 2 . 0 6 1 2 . 4 5 0 . 3 9 1 2 . 8 5 1 1 . 8 7 1 2 . 2 3 0 . 9 8 1 2 . 8 9 1 2 . 8 7 1 2 . 8 9 0 . 0 2 1 2 . 5 15 1 1 . 8 9 1 2 . 3 5 1 2 . 3 5 0 . 4 6 1 2 . 8 8 1 2 . 5 5 1 2 . 2 7 0 . 6 1 1 2 . 2 6 1 2 . 4 1 1 2 . 4 6 0 . 2 0 1 2 . 3 86 1 2 . 4 5 1 2 . 1 6 1 2 . 1 1 0 . 3 4 1 2 . 5 5 1 2 . 4 5 1 2 . 4 8 0 . 1 0 1 2 . 5 8 1 2 . 2 1 1 2 . 5 0 0 . 3 7 1 2 . 3 97 1 2 . 2 4 1 2 . 2 1 1 2 . 1 2 0 . 1 2 1 2 . 1 2 1 2 . 1 6 1 2 . 2 3 0 . 1 1 1 2 . 2 9 1 2 . 1 4 1 2 . 1 4 0 . 1 5 1 2 . 1 88 1 2 . 9 9 1 2 . 4 1 1 2 . 2 4 0 . 7 5 1 1 . 9 0 1 1 . 7 0 1 1 . 6 0 0 . 3 0 1 2 . 4 1 1 2 . 4 1 1 2 . 4 4 0 . 0 3 1 2 . 2 39 1 2 . 5 2 1 2 . 2 9 1 2 . 4 5 0 . 2 3 1 2 . 2 1 1 2 . 5 3 1 2 . 5 6 0 . 3 5 1 2 . 3 3 1 2 . 5 6 1 2 . 3 3 0 . 2 3 1 2 . 4 210 1 2 . 5 1 1 2 . 6 3 1 2 . 2 2 0 . 4 1 1 2 . 8 5 1 2 . 9 0 1 2 . 7 0 0 . 2 0 1 3 . 8 0 1 4 . 0 0 1 3 . 7 0 0 . 3 0 1 3 . 0 3T O T A L S 1 2 1 . 6 8 1 2 0 . 4 4 1 2 0 . 6 5 3 . 5 2 1 2 1 . 9 9 1 2 0 . 2 8 1 2 0 . 2 7 3 . 3 5 1 2 3 . 1 6 1 2 3 . 2 5 1 2 3 . 3 2 1 . 9 8 1 2 1 . 6 70 . 3 5 2 0 . 3 3 5 0 . 1 9 8Ra Rb RcS U M a 3 6 2 . 7 7 0 S U M b 3 6 2 . 5 4 0 S U M c 3 6 9 . 7 3 0Xa 1 2 . 0 9 2 Xb 1 2 . 0 8 5 Xc 1 2 . 3 2 4Ra 0 . 3 5 2 T R I A L D4 U C L r = R D 4 M A X X 1 2 . 3 2 4Rb 0 . 3 3 5 2 3 . 2 6 7 = 0 . 2 9 5 2 . 5 7 5 M I N X 1 2 . 0 8 5Rc 0 . 1 9 8 3 2 . 5 7 5 = 0 . 7 6 1 X d i f f 0 . 2 4 0S U M 0 . 8 8 5R 0 . 2 9 5xx第九版： 1999年 2月 132 MSA Ball Pull 試驗 RR 數據 S P B 0 0 1 R E P E A T A B IL IT Y A N D R E P R O D U C IB IL IT Y R E P O R T7 0 2 9 7 N B R : A P 0 0 3E q u i p m e n t D e s c r i p t i o n : D A G E D a t e : M a y 0 7 .39。 9 8C h a r a c t e r i s t i c s : B P T ( G / W : 1 . 0 M I L ) P e r f o r m e d b y : S p e c i f i c a t i o n : A B O V E 3 G RF r o m d a t a s h e e t : R = 0 . 2 9 5 Rp = 3 . 3 2 X d i f f = 0 . 2 4 0R e a s o n f o r R R s t u d y :N e w G a g e Q u a l i f i c a t i o n E v a l u a t e G a g e p e r f o r m a n c eX R o u t i n e E v a l u a t e R R o f g a g e O t h e rM e a s u r e m e n t U n i t A n a l y s i s % P r o c e s s A n a l y s i sR e p e a t a b i l i t y E q u i p m e n t V a r i a t i o n ( E V ) T R I A L S K1E V = R * K 1 2 4 . 6 5 % E V = 100 [ E V / T V ]= 0 . 9 0 0 3 3 . 0 5 = 1 6 . 4 0 % R e p r o d u c i b i l i t y A p p r a i s e r V a r i a t i o n ( A V )A V = % A V = 100 [ A V / T V ]= 1 1 . 4 1 %= 0 . 6 3 O p e r a t o r s K22 3 . 6 5 * * * n = n u m b e r o f p a r t s r = n u m b e r o f t r i a l s 3 2 . 7 0R e p e a t a b i l i t y R e p r o d u c i b i l i t y ( R R ) R R = P A R T K3 % R R = 100 [ R R / T V ]= 1 . 1 0 5 2 . 0 8 = 1 9 . 9 8 %P a r t V a i a t i o n ( P V ) 6 1 . 9 3 % P V = 100 [ P V / T V ]PV = Rp * K 3 7 1 . 8 2 = 9 7 . 9 8 %= 5 . 3 7 8 1 . 7 4T o t a l V a r i a t i o n ( T V ) 9 1 . 6 7TV = 10 1 . 6 2= 5 . 4 9C o n c l u s i o n :S a t i s f a c t o r y M a r g i n a l U n a c c e p t a b l e R e p e a t T r a i lR e p e a t a b i l i t y XR e p r o d u c i b i l i t y XR R XR e c o m m e n d a t i o n :2